这是我想出的。
基本上，我们有一个循环，可根据所需反应检查每个反应，然后删除旧消息并发送新消息（如果我们看到了所寻找的反应之一）。
from discord.ext import commands
bot = commands.Bot(command_prefix='!')
left = '?'
right = '?'
messages = ("1", "2", "3")
def predicate(message, l, r):
def check(reaction, user):
if reaction.message.id != message.id or user == bot.user:
return False
if l and reaction.emoji == left:
return True
if r and reaction.emoji == right:
return True
return False
return check
@bot.command(pass_context=True)
async def series(ctx):
index = 0
while True:
msg = await bot.say(messages[index])
l = index != 0
r = index != len(messages) - 1
if l:
await bot.add_reaction(msg, left)
if r:
await bot.add_reaction(msg, right)
# bot.wait_for_reaction
react, user = await bot.wait_for_reaction(check=predicate(msg, l, r))
if react.emoji == left:
index -= 1
elif react.emoji == right:
index += 1
await bot.delete_message(msg)
bot.run("TOKEN")
有人要求提供一种用于编辑消息的版本，而不是发送新消息，我也将其更新为最新版本：
@bot.command(pass_context=True)
async def series(ctx):
index = 0
msg = None
action = ctx.send
while True:
res = await action(content=messages[index])
if res is not None:
msg = res
l = index != 0
r = index != len(messages) - 1
if l:
await msg.add_reaction(left)
if r:
await msg.add_reaction(right)
react, user = await bot.wait_for('reaction_add', check=predicate(msg, l, r))
if react.emoji == left:
index -= 1
elif react.emoji == right:
index += 1
action = msg.edit
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