我的方法存在问题：
我为MultiPartResolver创建了一个bean。解决问题后的理解是，仅当你需要特定类型的文件或非常特定于应用程序的文件时，才定义此bean。尽管我希望对此有更多了解，并希望能从stackoverflow的技术人员那里听到。
当前问题的解决方案：
我会给出我的源代码，
HTML：
<div ng-controller="myCtrl">
<input type="file" file-model="myFile" />
<button ng-click="uploadFile()">upload me</button>
</div>
AngularJS：
var myApp = angular.module('myApp', []);
myApp.directive('fileModel', ['$parse', function ($parse) {
return {
restrict: 'A',
link: function(scope, element, attrs) {
var model = $parse(attrs.fileModel);
var modelSetter = model.assign;
element.bind('change', function(){
scope.$apply(function(){
modelSetter(scope, element[0].files[0]);
});
});
}
};
}]);
myApp.controller('myCtrl', ['$scope', '$http', function($scope, $http){
$scope.uploadFile = function(){
var file = $scope.myFile;
var fd = new FormData();
fd.append('file', file);
//We can send anything in name parameter,
//it is hard coded to abc as it is irrelavant in this case.
var uploadUrl = "/upload?name=abc";
$http.post(uploadUrl, fd, {
transformRequest: angular.identity,
headers: {'Content-Type': undefined}
})
.success(function(){
})
.error(function(){
});
}
}]);
spring：
@RequestMapping(value="/upload", method=RequestMethod.POST)
public String handleFileUpload(@RequestParam("name") String name,
@RequestParam("file") multipartfile file){
if (!file.isEmpty()) {
try {
byte[] bytes = file.getBytes();
bufferedoutputstream stream =
new bufferedoutputstream(new FileOutputStream(new File(name)));
stream.write(bytes);
stream.close();
return "You successfully uploaded " + name + "!";
} catch (Exception e) {
return "You Failed to upload " + name + " => " + e.getMessage();
}
} else {
return "You Failed to upload " + name + " because the file was empty.";
}
}
@arahant即使发送请求时在请求有效负载中没有看到任何文档base64内容，Angular也会发送multipartfile。
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