连续的子序列？寻呼Groupby博士，博士itertools.groupby：
>>> from itertools import groupby
>>> l = [240,200,160,4,0,0,0,0,4,4,4,0,0,0,1,1,1,1]
>>> [list(g) for k,g in groupby(l, lambda x: x != 0) if k]
[[240, 200, 160, 4], [4, 4, 4], [1, 1, 1, 1]]
甚至我们利用事实bool(0)是False和bool(any other integer)是True：
>>> [list(g) for k,g in groupby(l, bool) if k]
[[240, 200, 160, 4], [4, 4, 4], [1, 1, 1, 1]]
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