您可以这样做：
DECLARE @t TABLE(id int, n VARCHAR(50))
INSERT INTO @t VALUES
(1, 'ABCDEF'),
(2, 'EFGHIJKLMNOPQ')
;WITH cte AS
(SELECT id, n, SUBSTRING(n, 1, 1) c, 1 AS ind FROM @t
UNION ALL
SELECT id, n, SUBSTRING(n, ind + 1, 1), ind + 1 FROM cte WHERE LEN(n) > ind
)
SELECT *
FROM cte
PIVOT (MAX(c) FOR ind IN([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[12],[13],[14],[15])) p
输出：
id n 1 2 3 4 5 6 7 8 9 10 12 13 14 15
1 ABCDEF A B C D E F NULL NULL NULL NULL NULL NULL NULL NULL
2 EFGHIJKLMNOPQ E F G H I J K L M N P Q NULL NULL
这是动态版本：
DECLARE @l INT, @c VARCHAR(MAX) = ''
SELECT @l = MAX(LEN(n)) FROM PivotTable
WHILE @l > 0
BEGIN
SET @c = ',[' + CAST(@l AS VARCHAR(MAX)) + ']' + @c
SET @l = @l - 1
END
SET @c = STUFF(@c, 1, 1,'')
DECLARE @s NVARCHAR(MAX) = '
;WITH cte AS
(SELECT id, n, SUBSTRING(n, 1, 1) c, 1 AS ind FROM PivotTable
UNION ALL
SELECT id, n, SUBSTRING(n, ind + 1, 1), ind + 1 FROM cte WHERE LEN(n) > ind
)
SELECT *
FROM cte
PIVOT (MAX(c) FOR ind IN(' + @c + ')) p'
EXEC (@s)
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