获取汇总结果
from itertools import groupby
from operator import itemgetter
grouper = itemgetter("dept", "sku")
result = []
for key, grp in groupby(sorted(input_data, key = grouper), grouper):
temp_dict = dict(zip(["dept", "sku"], key))
temp_dict["qty"] = sum(item["qty"] for item in grp)
result.append(temp_dict)
from pprint import pprint
pprint(result)
[{'dept': '001', 'qty': 200, 'sku': 'bar'},
{'dept': '001', 'qty': 400, 'sku': 'foo'},
{'dept': '002', 'qty': 900, 'sku': 'baz'},
{'dept': '002', 'qty': 600, 'sku': 'qux'},
{'dept': '003', 'qty': 700, 'sku': 'foo'}]
为了获得平均值，您可以像这样简单地更改for循环内的内容
temp_dict = dict(zip(["dept", "sku"], key))
temp_list = [item["qty"] for item in grp]
temp_dict["avg"] = sum(temp_list) / len(temp_list)
result.append(temp_dict)
[{'avg': 200, 'dept': '001', 'sku': 'bar'},
{'avg': 200, 'dept': '001', 'sku': 'foo'},
{'avg': 450, 'dept': '002', 'sku': 'baz'},
{'avg': 600, 'dept': '002', 'sku': 'qux'},
{'avg': 700, 'dept': '003', 'sku': 'foo'}]
无论如何，我会像这样同时添加qty和和avg``dict
temp_dict = dict(zip(["dept", "sku"], key))
temp_list = [item["qty"] for item in grp]
temp_dict["qty"] = sum(temp_list)
temp_dict["avg"] = temp_dict["qty"] / len(temp_list)
result.append(temp_dict)
[{'avg': 200, 'dept': '001', 'qty': 200, 'sku': 'bar'},
{'avg': 200, 'dept': '001', 'qty': 400, 'sku': 'foo'},
{'avg': 450, 'dept': '002', 'qty': 900, 'sku': 'baz'},
{'avg': 600, 'dept': '002', 'qty': 600, 'sku': 'qux'},
{'avg': 700, 'dept': '003', 'qty': 700, 'sku': 'foo'}]
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