此解决方案不使用 。子查询会生成最近10,000天的日期，并且可以扩展为任意向前或向后的日期。
select a.Date
from (
select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a) + (1000 * d.a) ) DAY as Date
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as d
) a
where a.Date between '2010-01-20' and '2010-01-24'
Date
----------
2010-01-24
2010-01-23
2010-01-22
2010-01-21
2010-01-20
如果我们扩展子查询以生成近似值。100,000个数字（因此约有274年的日期），运行时间为0.0458秒。
顺便说一句，这是一种非常可移植的技术，该技术可以在大多数数据库中进行细微调整。
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