lst = list(gen)
lst
您也不能直接list在IPython中调用，因为它与列出代码行的命令冲突。
在此文件上测试：
def gen():
yield 1
yield 2
yield 3
yield 4
yield 5
import ipdb
ipdb.set_trace()
g1 = gen()
text = "aha" + "bebe"
mylst = range(10, 20)
运行时：
$ python code.py
> /home/javl/sand@R_577_2419@/so/debug/code.py(10)<module>()
9
---> 10 g1 = gen()
11
ipdb> n
> /home/javl/sand@R_577_2419@/so/debug/code.py(12)<module>()
11
---> 12 text = "aha" + "bebe"
13
ipdb> lst = list(g1)
ipdb> lst
[1, 2, 3, 4, 5]
ipdb> q
Exiting Debugger.
有调试器命令p和pp这种意愿print，并prettyprint跟随他们任何表情。
因此，您可以按以下方式使用它：
$ python code.py
> /home/javl/sand@R_577_2419@/so/debug/code.py(10)<module>()
9
---> 10 g1 = gen()
11
ipdb> n
> /home/javl/sand@R_577_2419@/so/debug/code.py(12)<module>()
11
---> 12 text = "aha" + "bebe"
13
ipdb> p list(g1)
[1, 2, 3, 4, 5]
ipdb> c
还有一个exec命令，通过在表达式前面加上来调用，该命令!强制调试器将您的表达式当作Python。
ipdb> !list(g1)
[]
欲了解更多详情，请参阅help p，help pp并help exec在调试程序时。
ipdb> help exec
(!) statement
Execute the (one-line) statement in the context of
the current stack frame.
The exclamation point can be omitted unless the first word
of the statement resembles a debugger command.
To assign to a global variable you must always prefix the
command with a 'global' command, e.g.:
(Pdb) global list_options; list_options = ['-l']
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