本机答案是否定的！
但是你可以这样做。
您的ajax请求：
$.ajax({
url: 'your-url-that-gives-zip-file.PHP',
dataType: 'JSON',
success: function(response){
if(response.zip) {
location.href = response.zip;
}
}
});
<?PHP
//Get your zip file code with and combine with http://youradress.com
$zipFile = 'http://youraddress.com/downloads/'.$zipFile;
echo json_encode(array('zip' => $zipFile));
?>
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