据我所知，Java没有与该WaitHandle.WaitAny方法类似的结构。
在我看来，这可以通过“ WaitableFuture”装饰器来实现：
public WaitableFuture<T>
extends Future<T>
{
private CountDownLatch countDownLatch;
WaitableFuture(CountDownLatch countDownLatch)
{
super();
this.countDownLatch = countDownLatch;
}
void doTask()
{
super.doTask();
this.countDownLatch.countDown();
}
}
尽管只有将其插入执行代码之前它才有效，否则执行代码将不会具有newdoTask()方法。但是，如果您不能以某种方式在执行之前获得对Future对象的控制，我真的看不到没有轮询就无法执行此操作的方法。
或者，如果将来总是在自己的线程中运行，那么您可以通过某种方式获得该线程。然后，您可以产生一个新线程来互相连接线程，然后在连接返回后处理等待机制……这确实很丑陋，但是会引起很多开销。而且，如果某些Future对象没有完成，则根据死线程，您可能会有很多阻塞线程。如果不小心，可能会泄漏内存和系统资源。
/**
* Extremely ugly way of implementing WaitHandle.WaitAny for Thread.Join().
*/
public static joinAny(Collection<Thread> threads, int numberToWaitFor)
{
CountDownLatch countDownLatch = new CountDownLatch(numberToWaitFor);
foreach(Thread thread in threads)
{
(new Thread(new JoinThreadHelper(thread, countDownLatch))).start();
}
countDownLatch.await();
}
class JoinThreadHelper
implements Runnable
{
Thread thread;
CountDownLatch countDownLatch;
JoinThreadHelper(Thread thread, CountDownLatch countDownLatch)
{
this.thread = thread;
this.countDownLatch = countDownLatch;
}
void run()
{
this.thread.join();
this.countDownLatch.countDown();
}
}
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