我找到了解决原始问题的方法。将其发布在此处作为答案，希望对你有所帮助。
jQuery：
var postUrl = "http://localhost:8000/ingredients/";
$('li').click(function(){
values = [1, 2];
var jsonText = JSON.stringify(values);
$.ajax({
url: postUrl,
type: 'POST',
data: jsonText,
Traditional: true,
dataType: 'html',
success: function(result){
$('#ingredients').append(result);
}
});
});
/成分/视图：
def ingredients(request):
if request.is_ajax():
ourid = json.loads(request.raw_post_data)
ingredients = Ingredience.objects.filter(food__id__in=ourid)
t = get_template('ingredients.html')
html = t.render(Context({'ingredients': ingredients,}))
return HttpResponse(html)
else:
html = '<p>This is not ajax</p>'
return HttpResponse(html)
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