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在Swift中从数组中删除重复的元素

在Swift中从数组中删除重复的元素

您可以自己滚动,例如这样( ):

func uniq<S : SequenceType, T : Hashable where S.Generator.Element == T>(source: S) -> [T] {
    var buffer = [T]()
    var added = Set<T>()
    for elem in source {
        if !added.contains(elem) {
            buffer.append(elem)
            added.insert(elem)
        }
    }
    return buffer
}

let vals = [1, 4, 2, 2, 6, 24, 15, 2, 60, 15, 6]
let uniqueVals = uniq(vals) // [1, 4, 2, 6, 24, 15, 60]

Swift 3版本:

func uniq<S : Sequence, T : Hashable>(source: S) -> [T] where S.Iterator.Element == T {
    var buffer = [T]()
    var added = Set<T>()
    for elem in source {
        if !added.contains(elem) {
            buffer.append(elem)
            added.insert(elem)
        }
    }
    return buffer
}

并作为扩展Array

extension Array where Element: Hashable {
    var uniques: Array {
        var buffer = Array()
        var added = Set<Element>()
        for elem in self {
            if !added.contains(elem) {
                buffer.append(elem)
                added.insert(elem)
            }
        }
        return buffer
    }
}
Swift 2022/1/1 18:19:46 有255人围观

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