这与用户最近在我的书 sql Antipatterns 的论坛上问我的问题非常相似。我给了他类似的答案：
$sql = "SELECT name, address, city FROM tableA JOIN tableB ON tableA.id = tableB.id";
$params = array();
$where = array();
if (isset($price) ) {
$where[] = '(price = :price)';
$params[':price'] = $price;
}
if (isset($sqft) ) {
$where[] = '(sqft >= :sqft)';
$params[':sqft'] = $sqft;
}
if (isset($bedrooms) ) {
$where[] = '(bedrooms >= :bedrooms)';
$params[':bedrooms'] = $bedrooms;
}
if ($where) {
$sql .= ' WHERE ' . implode(' AND ', $where);
}
$stmt = $dbh->prepare($sql);
$stmt->execute($params);
$result_set = $stmt->fetchAll(PDO::FETCH_ASSOC);
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