这是从我写的一些示例代码中剪切和粘贴的,希望它应该提供基础知识。目前只支持文件数据和表单数据。
public class PostData
{
private List<PostDataParam> m_Params;
public List<PostDataParam> Params
{
get { return m_Params; }
set { m_Params = value; }
}
public PostData()
{
m_Params = new List<PostDataParam>();
// Add sample param
m_Params.Add(new PostDataParam("email", "MyEmail", PostDataParamType.Field));
}
/// <summary>
/// Returns the parameters array formatted for multi-part/form data
/// </summary>
/// <returns></returns>
public string GetPostData()
{
// Get boundary, default is --AaB03x
string boundary = ConfigurationManager.AppSettings["ContentBoundary"].ToString();
StringBuilder sb = new StringBuilder();
foreach (PostDataParam p in m_Params)
{
sb.AppendLine(boundary);
if (p.Type == PostDataParamType.File)
{
sb.AppendLine(string.Format("Content-Disposition: file; name=\"{0}\"; filename=\"{1}\"", p.Name, p.FileName));
sb.AppendLine("Content-Type: text/plain");
sb.AppendLine();
sb.AppendLine(p.Value);
}
else
{
sb.AppendLine(string.Format("Content-Disposition: form-data; name=\"{0}\"", p.Name));
sb.AppendLine();
sb.AppendLine(p.Value);
}
}
sb.AppendLine(boundary);
return sb.ToString();
}
}
public enum PostDataParamType
{
Field,
File
}
public class PostDataParam
{
public PostDataParam(string name, string value, PostDataParamType type)
{
Name = name;
Value = value;
Type = type;
}
public string Name;
public string FileName;
public string Value;
public PostDataParamType Type;
}
要发送数据,您需要:
HttpWebRequest oRequest = null;
oRequest = (HttpWebRequest)HttpWebRequest.Create(oURL.URL);
oRequest.ContentType = "multipart/form-data";
oRequest.Method = "POST";
PostData pData = new PostData();
byte[] buffer = encoding.GetBytes(pData.GetPostData());
// Set content length of our data
oRequest.ContentLength = buffer.Length;
// Dump our buffered postdata to the stream, booyah
oStream = oRequest.GetRequestStream();
oStream.Write(buffer, 0, buffer.Length);
oStream.Close();
// get the response
oResponse = (HttpWebResponse)oRequest.GetResponse();
希望那很清楚,我已经从几个来源剪切和粘贴,以使内容更整洁。