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SQL / Postgres日期时间划分/规范化

SQL / Postgres日期时间划分/规范化

获取所需的行,请先使用set returning函数横向联接。从那里,使用CASE语句和日期算术提取相关值。

这是一个使您入门的示例:

with data as (
  select id, start_date, end_date
  from (values
    (1, '2014-12-02 14:12:00+00'::timestamptz, '2014-12-03 06:45:00+00'::timestamptz),
    (2, '2014-12-05 15:25:00+00'::timestamptz, '2014-12-05 07:29:00+00'::timestamptz)
  ) as rows (id, start_date, end_date)
)
select data.id,
      case days.d = date_trunc('day', data.start_date)
        when true then data.start_date
        else days.d
      end as start_date,
      case days.d = date_trunc('day', data.end_date)
        when true then data.end_date
        else days.d + interval '1 day' - interval '1 sec'
      end as end_date
from data
join generate_series(
      date_trunc('day', data.start_date),
      date_trunc('day', data.end_date),
      '1 day'
      ) as days (d)
      on days.d >= date_trunc('day', data.start_date)
      and days.d <= date_trunc('day', data.end_date)

 id |       start_date       |        end_date        
----+------------------------+------------------------
  1 | 2014-12-02 15:12:00+01 | 2014-12-02 23:59:59+01
  1 | 2014-12-03 00:00:00+01 | 2014-12-03 07:45:00+01
  2 | 2014-12-05 16:25:00+01 | 2014-12-05 08:29:00+01
(3 rows)

顺便说一句,根据您的工作,使用日期范围可能更有意义:

with data as (
  select id, start_date, end_date
  from (values
    (1, '2014-12-02 14:12:00+00'::timestamptz, '2014-12-03 06:45:00+00'::timestamptz),
    (2, '2014-12-05 07:25:00+00'::timestamptz, '2014-12-05 15:29:00+00'::timestamptz)
  ) as rows (id, start_date, end_date)
)
select data.id,
      tstzrange(data.start_date, data.end_date)
from data;

 id |                      tstzrange                      
----+-----------------------------------------------------
  1 | ["2014-12-02 15:12:00+01","2014-12-03 07:45:00+01")
  2 | ["2014-12-05 08:25:00+01","2014-12-05 16:29:00+01")
(2 rows)
SQLServer 2022/1/1 18:53:14 有388人围观

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