我认为是这样的：
select link, count(*)-1 as "RESULT COUNT"
from (
select connect_by_root(link_id) link
from my_table
connect by nocycle parent_link_id = prior link_id
start with parent_link_id is null)
group by link
order by 1 asc
如何获取Oracle树层次结构中所有父项的子项总数？
如何获取Oracle树层次结构中所有父项的子项总数？
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