如果您想建立联系，则可以执行以下操作：
select s.*
from scores s
where s.score = (select max(s2.score) from scores s2 where s2.level = s.level);
通过汇总以下内容，您可以在每个级别获得一行：
select s.level, s.score, group_concat(s.user_id)
from scores s
where s.score = (select max(s2.score) from scores s2 where s2.level = s.level)
group by s.level, s.score;
602392714
清零编程群