rangelist在python3中不返回a ，因此range(2, 10) + ["J", "Q", "K", "A"]不起作用，但是list(range(2, 10)) + ["J", "Q", "K", "A"]可以。您还可以itertools.chain用来串联可迭代对象：
from itertools import chain
chain(range(2, 10), ["J", "Q", "K", "A"])
# or even shorter:
chain(range(2, 10), "JQKA") # as strings themselves are iterables
# so this comprehension will work
deck = [
(value, suit)
for value in chain(range(2, 10), "JQKA")
for suit in "HCDS"
]
嵌套的理解当然会构成笛卡尔积，您也可以将util用于以下方面：
from itertools import product
deck = list(product(chain(range(2, 10), "JQKA"), "HCDS"))
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