腌制一个类时，将 __腌制该类 的 名称@L_404_3@。如果class_decorator返回一个 名称 未在模块顶层定义的新类，则会出现错误：
PicklingError: Can't pickle <class '__main__.new_cls'>: it's not found as __main__.new_cls
您可以通过将新修饰的类命名为未修饰的类来避免该错误：
new_cls.__name__ = cls.__name__
然后代码运行无误：
import pickle
def class_decorator(cls):
class new_cls(cls):
def run(self, *args, **kwargs):
print 'In decorator'
super(new_cls,self).run(*args, **kwargs)
new_cls.__name__ = cls.__name__
return new_cls
@class_decorator
class cls(object):
def run(self):
print 'called'
a = cls()
print(a)
# <__main__.cls object at 0x7f57d3743650>
a.run()
# In decorator
# called
s = pickle.dumps(a)
# Note "cls" in the `repr(s)` below refers to the name of the class. This is
# what `pickle.loads` is using to unpickle the string
print(repr(s))
# 'ccopy_reg\n_reconstructor\np0\n(c__main__\ncls\np1\nc__builtin__\nobject\np2\nNtp3\nRp4\n.'
b = pickle.loads(s)
print(b)
# <__main__.cls object at 0x7f57d3743690>
b.run()
# In decorator
# called
602392714
清零编程群