从这里改编答案，看起来应该像
public static String withSuffix(long count) {
if (count < 1000) return "" + count;
int exp = (int) (Math.log(count) / Math.log(1000));
return String.format("%.1f %c",
count / Math.pow(1000, exp),
"kMGTPE".charAt(exp-1));
}
for (long num : new long[] { 0, 27, 999, 1000, 110592,
28991029248L, 9223372036854775807L })
System.out.printf("%20d: %8s%n", num, withSuffix(num));
0: 0
27: 27
999: 999
1000: 1.0 k
110592: 110.6 k
28991029248: 29.0 G
9223372036854775807: 9.2 E
602392714
清零编程群