我认为您不需要WordNet来查找专有名词，我建议使用词性标记器pos_tag。
from nltk.tag import pos_tag
sentence = "Michael Jackson likes to eat at McDonalds"
tagged_sent = pos_tag(sentence.split())
# [('Michael', 'NNP'), ('Jackson', 'NNP'), ('likes', 'VBZ'), ('to', 'TO'), ('eat', 'VB'), ('at', 'IN'), ('McDonalds', 'NNP')]
propernouns = [word for word,pos in tagged_sent if pos == 'NNP']
# ['Michael','Jackson', 'McDonalds']
您可能没有，因为很满意Michael，并Jackson分裂成2个令牌，则可能需要更复杂的东西，如名称实体恶搞。
如penntreebank标签集所记录的那样，对于所有格名词而言，只要找到POS标签，您就可以轻松找到http://www.mozart-oz.org/mogul/doc/lager/brill-tagger/penn.html。但往往是恶搞不标记POS时，它的一个NNP。
from nltk.tag import pos_tag
sentence = "Michael Jackson took Daniel Jackson's hamburger and Agnes' fries"
tagged_sent = pos_tag(sentence.split())
# [('Michael', 'NNP'), ('Jackson', 'NNP'), ('took', 'VBD'), ('Daniel', 'NNP'), ("Jackson's", 'NNP'), ('hamburger', 'NN'), ('and', 'CC'), ("Agnes'", 'NNP'), ('fries', 'NNS')]
possessives = [word for word in sentence if word.endswith("'s") or word.endswith("s'")]
# ["Jackson's", "Agnes'"]
另外，您可以使用NLTK，ne_chunk但是除非您担心从句子中获得哪种专有名词，否则它似乎没有其他作用：
>>> from nltk.tree import Tree; from nltk.chunk import ne_chunk
>>> [chunk for chunk in ne_chunk(tagged_sent) if isinstance(chunk, Tree)]
[Tree('PERSON', [('Michael', 'NNP')]), Tree('PERSON', [('Jackson', 'NNP')]), Tree('PERSON', [('Daniel', 'NNP')])]
>>> [i[0] for i in list(chain(*[chunk.leaves() for chunk in ne_chunk(tagged_sent) if isinstance(chunk, Tree)]))]
['Michael', 'Jackson', 'Daniel']
使用ne_chunk有点冗长，并不能使您拥有所有格。
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