没有用于timedelta对象的内置格式化程序，但是你自己可以很容易地做到这一点：
days, seconds = duration.days, duration.seconds
hours = days * 24 + seconds // 3600
minutes = (seconds % 3600) // 60
seconds = seconds % 60
或者，等效地，如果你使用的是Python 2.7+或3.2+：
seconds = duration.total_seconds()
hours = seconds // 3600
minutes = (seconds % 3600) // 60
seconds = seconds % 60
现在，你可以根据需要打印它：
'{} minutes, {} hours'.format(minutes, hours)
例如：
def convert_timedelta(duration):
days, seconds = duration.days, duration.seconds
hours = days * 24 + seconds // 3600
minutes = (seconds % 3600) // 60
seconds = (seconds % 60)
return hours, minutes, seconds
td = datetime.timedelta(2, 7743, 12345)
hours, minutes, seconds = convert_timedelta(td)
print '{} minutes, {} hours'.format(minutes, hours)
这将打印：
9 minutes, 50 hours
如果要获取“ 10分钟1小时”而不是“ 10分钟1小时”，则也需要手动执行此操作：
print '{} minute{}, {} hour{}'.format(minutes, 's' if minutes != 1 else '',
hours, 's' if minutes != 1 else '')
或者，你可能想编写一个english_plural函数’s’为你完成这些操作，而不是重复自己。
从你的评论看来，你实际上是想让日子分开。这甚至更容易：
def convert_timedelta(duration):
days, seconds = duration.days, duration.seconds
hours = seconds // 3600
minutes = (seconds % 3600) // 60
seconds = (seconds % 60)
return days, hours, minutes, seconds
如果要将其转换为单个值以存储在数据库中，然后将该单个值转换回以对其进行格式化，请执行以下操作：
def dhms_to_seconds(days, hours, minutes, seconds):
return (((days * 24) + hours) * 60 + minutes) * 60 + seconds
def seconds_to_dhms(seconds):
days = seconds // (3600 * 24)
hours = (seconds // 3600) % 24
minutes = (seconds // 60) % 60
seconds = seconds % 60
return days, hours, minutes, seconds
因此，将其放在一起：
def store_timedelta_in_database(thingy, duration):
seconds = dhms_to_seconds(*convert_timedelta(duration))
db.execute('INSERT INTO foo (thingy, duration) VALUES (?, ?)',
thingy, seconds)
db.commit()
def print_timedelta_from_database(thingy):
cur = db.execute('SELECT duration FROM foo WHERE thingy = ?', thingy)
seconds = int(cur.fetchone()[0])
days, hours, minutes, seconds = seconds_to_dhms(seconds)
print '{} took {} minutes, {} hours, {} days'.format(thingy, minutes, hours, days)
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