是的，您可以使用JsonConvert.PopulateObject()第二个JSON字符串来填充现有对象的属性。
这是一个例子：
string json1 = @"
{
""CID"": ""13579"",
""jsonrpc"": ""something"",
""id"": ""24680""
}";
Account account = JsonConvert.DeserializeObject<Account>(json1);
string json2 = @"
{
""mail"": [ ""abc@example.com"", ""def@example.org"" ],
""uid"": [ ""87654"", ""192834"" ],
""userPassword"": [ ""superSecret"", ""letMeInNow!"" ]
}";
JsonConvert.PopulateObject(json2, account);
Console.WriteLine("CID: " + account.CID);
Console.WriteLine("jsonrpc: " + account.jsonrpc);
Console.WriteLine("id: " + account.id);
Console.WriteLine("mail: " + string.Join(", ", account.mail));
Console.WriteLine("uid: " + string.Join(", ", account.uid));
Console.WriteLine("userPassword: " + string.Join(", ", account.userPassword));
输出：
CID: 13579
jsonrpc: something
id: 24680
mail: abc@example.com, def@example.org
uid: 87654, 192834
userPassword: superSecret, letMeInNow!
小提琴：https ://dotnetfiddle.net/621bfV
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