您可以使用@L_502_0@和urlunsplit()分解并重建URL，然后urlencode()在解析的查询字符串上使用：
from urllib import urlencode
from urlparse import parse_qs, urlsplit, urlunsplit
def set_query_parameter(url, param_name, param_value):
"""Given a URL, set or replace a query parameter and return the
modified URL.
>>> set_query_parameter('http://example.com?foo=bar&biz=baz', 'foo', 'stuff')
'http://example.com?foo=stuff&biz=baz'
"""
scheme, netloc, path, query_string, fragment = urlsplit(url)
query_params = parse_qs(query_string)
query_params[param_name] = [param_value]
new_query_string = urlencode(query_params, doseq=True)
return urlunsplit((scheme, netloc, path, new_query_string, fragment))
如下使用它：
>>> set_query_parameter("/scr.cgi?q=1&ln=0", "SOMESTRING", 1)
'/scr.cgi?q=1&ln=0&SOMESTRING=1'
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