这是格式很漂亮的输入，您可以通过拆分每一行轻松地获取列和??数据列表，然后为其创建字典。
这是一个没有正则表达式的简单脚本
lines = open("/proc/net/dev", "r").readlines()
columnLine = lines[1]
_, receiveCols , transmitCols = columnLine.split("|")
receiveCols = map(lambda a:"recv_"+a, receiveCols.split())
transmitCols = map(lambda a:"trans_"+a, transmitCols.split())
cols = receiveCols+transmitCols
faces = {}
for line in lines[2:]:
if line.find(":") < 0: continue
face, data = line.split(":")
faceData = dict(zip(cols, data.split()))
faces[face] = faceData
import pprint
pprint.pprint(faces)
它输出
{' lo': {'recv_bytes': '7056295',
'recv_compressed': '0',
'recv_drop': '0',
'recv_errs': '0',
'recv_fifo': '0',
'recv_frame': '0',
'recv_multicast': '0',
'recv_packets': '12148',
'trans_bytes': '7056295',
'trans_carrier': '0',
'trans_colls': '0',
'trans_compressed': '0',
'trans_drop': '0',
'trans_errs': '0',
'trans_fifo': '0',
'trans_packets': '12148'},
' eth0': {'recv_bytes': '34084530',
'recv_compressed': '0',
'recv_drop': '0',
'recv_errs': '0',
'recv_fifo': '0',
'recv_frame': '0',
'recv_multicast': '0',
'recv_packets': '30599',
'trans_bytes': '6170441',
'trans_carrier': '0',
'trans_colls': '0',
'trans_compressed': '0',
'trans_drop': '0',
'trans_errs': '0',
'trans_fifo': '0',
'trans_packets': '32377'}}
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