尝试以下正则表达式:
^(?:[\p{L}\p{Mn}\p{Pd}\'\x{2019}]+\s[\p{L}\p{Mn}\p{Pd}\'\x{2019}]+\s?)+$
在PHP中,这转换为:
if (preg_match('~^(?:[\p{L}\p{Mn}\p{Pd}\'\x{2019}]+\s[\p{L}\p{Mn}\p{Pd}\'\x{2019}]+\s?)+$~u', $name) > 0)
{
// valid
}
您应该这样阅读:
^ # start of subject
(?: # match this:
[ # match a:
\p{L} # Unicode letter, or
\p{Mn} # Unicode accents, or
\p{Pd} # Unicode hyphens, or
\' # single quote, or
\x{2019} # single quote (alternative)
]+ # one or more times
\s # any kind of space
[ #match a:
\p{L} # Unicode letter, or
\p{Mn} # Unicode accents, or
\p{Pd} # Unicode hyphens, or
\' # single quote, or
\x{2019} # single quote (alternative)
]+ # one or more times
\s? # any kind of space (0 or more times)
)+ # one or more times
$ # end of subject
老实说,我不知道如何将其移植到Javascript,我什至不确定Javascript是否支持Unicode属性,但是在PHP PCRE中,@ IDEOne.com似乎可以完美地工作:
$names = array
(
'Alix',
'André Svenson',
'H4nn3 Andersen',
'Hans',
'John Elkjærd',
'Kristoffer la Cour',
'Marco d\'Almeida',
'Martin Henriksen!',
);
foreach ($names as $name)
{
echo sprintf('%s is %s' . "\n", $name, (preg_match('~^(?:[\p{L}\p{Mn}\p{Pd}\'\x{2019}]+\s[\p{L}\p{Mn}\p{Pd}\'\x{2019}]+\s?)+$~u', $name) > 0) ? 'valid' : 'invalid');
}
很抱歉,我无法在Javascript部分方面为您提供帮助,但可能有人会在这里帮您。
要替换无效字符,尽管我不确定为什么需要这样做,但您只需要对其稍作更改即可:
$name = preg_replace('~[^\p{L}\p{Mn}\p{Pd}\'\x{2019}\s]~u', '$1', $name);
请注意,您始终需要使用 u 修饰符。