这是Luke Sneeringer建议的“自定义表单”解决方案。无论如何，我对缺少这个问题（相当自然且可能很常见）的现成Django解决方案感到惊讶。我想念什么吗？
from django import forms
from django.db import models
from django.contrib import admin
class Foo(models.Model):
pass
class Bar(models.Model):
foo = models.ForeignKey(Foo)
class FooForm(forms.ModelForm):
class Meta:
model = Foo
bars = forms.ModelMultipleChoiceField(queryset=Bar.objects.all())
def __init__(self, *args, **kwargs):
super(FooForm, self).__init__(*args, **kwargs)
if self.instance:
self.fields['bars'].initial = self.instance.bar_set.all()
def save(self, *args, **kwargs):
# FIXME: 'commit' argument is not handled
# TODO: Wrap reassignments into transaction
# NOTE: PrevIoUsly assigned Foos are silently reset
instance = super(FooForm, self).save(commit=False)
self.fields['bars'].initial.update(foo=None)
self.cleaned_data['bars'].update(foo=instance)
return instance
class FooAdmin(admin.ModelAdmin):
form = FooForm
你需要InlineModelAdmin （请参见InlineModelAdmin文档）
简短的示例代码：
class StudentAdminInline(admin.TabularInline):
model = Student
class ClassAdmin(admin.ModelAdmin):
inlines = (StudentAdminInline, )
admin.site.register(Class, ClassAdmin)
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